|
|
|
| |
Advertisment
|
| |
Wikipedia
Zorica Pantic, born circa 1951 in the former Yugoslavia, is a college administrator and professor of electrical engineering. In 2005 she was appointed the fourth president of Wentworth Institute of Technology in Boston.
Pantic was previously the fo...
http://en.wikipedia.org/wiki/Zorica_Pantic
|
| |
Links
|
|
|
| |
Blogs
http://percentsinew.blogspot.com/2008/07/3200i.html3200i (by: Shopkeeper)
PhDpScholh shop in Signa w Processing /l Communication - University of New South Wales, Australia. PhD Scholarship Signal Processing/Communic ations School of Electrical Engineering and Computer Science New South Wales, Australia ...
http://1stqwe.seesaa.net/article/103182986.htmlBu0026#39;zBu0026#39;z?BAD COMMUNICATION(UGA??????)? (by: are)
¦??????. B'zB'z?BAD COMMUNICATION(UGA??????)?. ¦?? B'z - Ocean (?? ???) (??? piano version) ¦??????. B’z?????1?!????????? - MSN?????? ...
http://www.bioportfolio.co.uk/cgi-bin/dialogserver.exe?CMDu003dhit.displayMdocu0026IDu003d1684787u0026HITNOu003d8u0026MSIZEu003d1000u0026LANGUAGEu003denu0026FILEu003ddoc.NEWSFEEDu0026SAVEQUERY00u003dCDIA Reveals Industry Move towards SMS For Clinical Trials ... (by: unknown)
Pharmaceutical Online ,
|
| |
Videos
B'z - Bad Communication MS Live
Joan Ranquet animal communication
Joan Ranquet animal communication
|
|
|
| |
Downloads
Zacharias ravi communication in babel mp3
Vzochat video chat 5 5 1 - free video communication via the internet zip
|
| |
Definition
No definitions found for z communication.
|
| |
Questions & Answers
Does it seem that issues from "A" to "Z" have all become too political ? What's it all about ?
Communication skills ; weather ; sports ; religion ; news ; radio ; kindergarteners ; family living ; The flag ; Christmas ; cars ; the Internet ; entertainment and award shows . Even law-breakers have become a political issue- instead of criminals. . Who is responsible for this ? Can it ever end ? Will they ever just "SHUT UP AND SING" ?
It has always been political. You just hear a lot more about it because of industry lobbying that creates massive advertising campaigns to get their point across.
Internet Communication shield blocking access?
I installed Spy Sweeper in my lap top (VISTA) and every 5 seconds there is a warning saying "the internet communication service has block access to : ADGATE.INFO or to ADS.Z-QUEST or... many more Is this normal? I else have the same program in another computer and never shows that is blocking anything. Thank you in advance!
You appear to have malware.
Get adaware, spybot, windows defender. All are free.
Install them.
Run them.
re-boot in safe mode.
run them again, and run ad/remove programs.
Statistic problem for a Communication course??
Please could someone help me figure out how to do this question? It asks: You survey 2,001 ppl in the US on various issues and find 95% oppose pollution, 2% like statisticians, 54% would re-elect the President, and 28% play tennis. What is the sampling error of the 95% confidence lvl for each of these proportions and why does it vary?
So far I can do:
P +/- = ZvP(1-P) over(÷) N-1
P +/- = 1.96v.95(1-.95) over(÷) 2001-1
1.96v.95x0.05 ÷ 2000
but then I get stuck, mostly because the number I get differs from the answer he gave us for it. The answers are supossed to be: 1A: .95% 1B: .61% 1C: 2.18% 1D: 1.97%
Obviously, I'm not getting to that final answer point and I don't know what to do next...can anyone help me? It would help me more to answer 1 or 2 by showing me and then let me use the same method for the others to try and reach the correct answer. I'm very bad at math so if you could keep it simple(terms and explanation), it would help me understand it better. Thank you
I appreciate the help but the answers were given to us as :
1A: .95% 1B: .61% 1C: 2.18% 1D: 1.97% The start of the problem is the formula we were given to figure it out so you do need to divide into 2000 eventually. The answers you have don't match what I'm supossed to get, and I think I got something similar to what you did too, that's why I need help because I need to get the %'s from above in the end. Thanks for trying though.
You are given:
A sample proportion
A sample size
A Confidence Level
And you need to find the "sampling error." I don't know if by this you mean the standard error, or the margin of error. So I'll show you how to find both.
Firstly, a confidence interval is structured as such: p +- z*(standard error)
so I'll show you how to find the margin of error, which is z*(standarderror). Then, if what you want is the standard error, just divide by z*.
Since we're dealing w/ a 95% Conf. Lvl, our z* = 1.96 (use the more accurate result as calculated by your calculator for the rest of the stuff so you don't get rounding error). Now we just need to find the standard error.
In a 1-Proportion Z-Interval, the standard error is: sqrt(p*(1-p)/n), where p is the sample proportion (p-hat, actually, not p). I see you have some /(n-1) stuff going on over there. I don't believe you need to divide by n-1 for this.
So, for 2% like statisticians: 1.96 * sqrrt(.02*.98/2001) = 1.96 * .009897 = .0193978
For 54% would re-elect the prez: 1.96 * sqrrt(.54*.46/2001) = 1.96 * .0111417 = .0218374
For 28% play tennis, 1.96 * sqrrt(.28*.72/2001) = 1.96*.0139408 = .0273236
Hope I got all that right. Been a while since I took any stats courses....
|
|
